Cursus Raku / Addendum 🆕 / Genera et machinae textuales / Obiecta et classes / Exercises / Quis quadrans

Solutio: Quis quadrans

Ecce solutio possibilis huius exercitationis.

Codex

class Point {
    has $.x;
    has $.y;

    method quadrant {
        return 'origin'     if $.x == 0 && $.y == 0;
        return 'on an axis' if $.x == 0 || $.y == 0;
        return $.x > 0 ?? ($.y > 0 ?? 'first'  !! 'fourth')
                       !! ($.y > 0 ?? 'second' !! 'third');
    }
}

for Point.new(x => 3, y => 4),  Point.new(x => -2, y => 5),
    Point.new(x => -1, y => -6), Point.new(x => 0, y => 3) -> $point {
    say "({$point.x}, {$point.y}): {$point.quadrant}";
}

🦋 Inveni codicem fontem in archivo point-quadrant.raku.

Exitus

(3, 4): first
(-2, 5): second
(-1, -6): third
(0, 3): on an axis

Commentarii

  1. Duo return matura casus speciales primum tractant — originem et puncta in axe iacentia — ita ut reliquum methodi utramque coordinatam non nihil esse sumere possit.

  2. Ternarium nidificatum deinde quadrantem ex signis ipsorum x et y legit: x positivum quadrantem primum vel quartum significat, x negativum secundum vel tertium.

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